Rouse Polymer — Normal Mode Relaxation

Gaussian chain dynamics • Normal mode decomposition • τ_p ∝ N²/p²

Chain Length N30

Temperature kT1.00

Friction ξ1.0

Bond stiffness k5.0

R² end-to-end—

Rg² (gyration)—

τ_Rouse (est.)—

Rouse: ξ·∂r_n/∂t = k·∂²r_n/∂n² + η(t) | Normal modes: X_p = (1/N)∫₀ᴺ r_n·cos(pπn/N) dn | τ_p = ξN²/(3π²kp²)