Maxwell-Boltzmann Distribution
Speed distribution of an ideal gas at thermal equilibrium
Controls
Temperature T (K)
300
Second T (K)
1000
Molar mass M (g/mol)
28
Particles
200
f(v) = 4π(m/2πkT)^(3/2) v² exp(−mv²/2kT)
v_p = √(2kT/m) — most probable
v_mean = √(8kT/πm) — mean
v_rms = √(3kT/m) — root mean square
Dots in box: speeds drawn from MB distribution, colored by speed.