Catenary y=a·cosh(x/a)
Parabola (wrong)
Chain beads
Euler-Lagrange equation:
d/dx(y'/√(1+y'²)) = c
Solution:
y = a·cosh(x/a) + b
d/dx(y'/√(1+y'²)) = c
Solution:
y = a·cosh(x/a) + b
A hanging chain minimizes gravitational potential energy — Euler-Lagrange gives y = a·cosh(x/a)